105443543050313 has 4 divisors (see below), whose sum is σ = 113554584823428. Its totient is φ = 97332501277200.

The previous prime is 105443543050309. The next prime is 105443543050327. The reversal of 105443543050313 is 313050345344501.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 68437697653264 + 37005845397049 = 8272708^2 + 6083243^2 .

It is a cyclic number.

It is not a de Polignac number, because 105443543050313 - 2² = 105443543050309 is a prime.

It is a super-2 number, since 2×105443543050313² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (105443543050303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4055520886538 + ... + 4055520886563.

It is an arithmetic number, because the mean of its divisors is an integer number (28388646205857).

Almost surely, 2^{105443543050313} is an apocalyptic number.

105443543050313 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

105443543050313 is a deficient number, since it is larger than the sum of its proper divisors (8111041773115).

105443543050313 is an equidigital number, since it uses as much as digits as its factorization.

105443543050313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8111041773114.

The product of its (nonzero) digits is 648000, while the sum is 41.

Adding to 105443543050313 its reverse (313050345344501), we get a palindrome (418493888394814).

The spelling of 105443543050313 in words is "one hundred five trillion, four hundred forty-three billion, five hundred forty-three million, fifty thousand, three hundred thirteen".