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105444130153 = 498532115101
BaseRepresentation
bin110001000110011110…
…1011011110101101001
3101002011120201210211211
41202030331123311221
53211422144131103
6120235041353121
710422001214035
oct1421475336551
9332146653754
10105444130153
114079a50a71a
12185290387a1
139c3569132b
1451640d31c5
152b2217036d
hex188cf5bd69

105444130153 has 4 divisors (see below), whose sum is σ = 105446295108. Its totient is φ = 105441965200.

The previous prime is 105444130111. The next prime is 105444130201. The reversal of 105444130153 is 351031444501.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 26891736169 + 78552393984 = 163987^2 + 280272^2 .

It is a cyclic number.

It is not a de Polignac number, because 105444130153 - 213 = 105444121961 is a prime.

It is a super-2 number, since 2×1054441301532 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (105444130553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1007698 + ... + 1107403.

It is an arithmetic number, because the mean of its divisors is an integer number (26361573777).

Almost surely, 2105444130153 is an apocalyptic number.

It is an amenable number.

105444130153 is a deficient number, since it is larger than the sum of its proper divisors (2164955).

105444130153 is an equidigital number, since it uses as much as digits as its factorization.

105444130153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2164954.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 105444130153 its reverse (351031444501), we get a palindrome (456475574654).

The spelling of 105444130153 in words is "one hundred five billion, four hundred forty-four million, one hundred thirty thousand, one hundred fifty-three".

Divisors: 1 49853 2115101 105444130153