Search a number
-
+
105535314345 = 357989059337
BaseRepresentation
bin110001001001001100…
…1010001100110101001
3101002101221022110001010
41202102121101212221
53212114020024340
6120252100014133
710424156241126
oct1422231214651
9332357273033
10105535314345
1140836a2a75a
1218553691349
139c4b539286
14517226b74d
152b2a182b80
hex18926519a9

105535314345 has 16 divisors (see below), whose sum is σ = 170993928960. Its totient is φ = 55573025664.

The previous prime is 105535314331. The next prime is 105535314371. The reversal of 105535314345 is 543413535501.

It is not a de Polignac number, because 105535314345 - 219 = 105534790057 is a prime.

It is a super-2 number, since 2×1055353143452 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44528484 + ... + 44530853.

It is an arithmetic number, because the mean of its divisors is an integer number (10687120560).

Almost surely, 2105535314345 is an apocalyptic number.

105535314345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

105535314345 is a deficient number, since it is larger than the sum of its proper divisors (65458614615).

105535314345 is an equidigital number, since it uses as much as digits as its factorization.

105535314345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 89059424.

The product of its (nonzero) digits is 270000, while the sum is 39.

Adding to 105535314345 its reverse (543413535501), we get a palindrome (648948849846).

The spelling of 105535314345 in words is "one hundred five billion, five hundred thirty-five million, three hundred fourteen thousand, three hundred forty-five".

Divisors: 1 3 5 15 79 237 395 1185 89059337 267178011 445296685 1335890055 7035687623 21107062869 35178438115 105535314345