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105555100153 = 1943862314983
BaseRepresentation
bin110001001001110010…
…0110000000111111001
3101002110022112200001211
41202103210300013321
53212134101201103
6120254044043121
710424516355526
oct1422344600771
9332408480054
10105555100153
1140847114068
121855a2334a1
139c52676059
145174b3c14d
152b2bc9036d
hex18939301f9

105555100153 has 16 divisors (see below), whose sum is σ = 113715374080. Its totient is φ = 97656151824.

The previous prime is 105555100151. The next prime is 105555100207. The reversal of 105555100153 is 351001555501.

It is a cyclic number.

It is not a de Polignac number, because 105555100153 - 21 = 105555100151 is a prime.

It is a super-2 number, since 2×1055551001532 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (105555100151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7037500 + ... + 7052482.

It is an arithmetic number, because the mean of its divisors is an integer number (7107210880).

Almost surely, 2105555100153 is an apocalyptic number.

It is an amenable number.

105555100153 is a deficient number, since it is larger than the sum of its proper divisors (8160273927).

105555100153 is a wasteful number, since it uses less digits than its factorization.

105555100153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23668.

The product of its (nonzero) digits is 9375, while the sum is 31.

Adding to 105555100153 its reverse (351001555501), we get a palindrome (456556655654).

The spelling of 105555100153 in words is "one hundred five billion, five hundred fifty-five million, one hundred thousand, one hundred fifty-three".

Divisors: 1 19 43 817 8623 14983 163837 284677 370789 644269 7044991 12241111 129198409 2454769771 5555531587 105555100153