1056031214017 has 4 divisors (see below), whose sum is σ = 1137264384340. Its totient is φ = 974798043696.

The previous prime is 1056031213973. The next prime is 1056031214081. The reversal of 1056031214017 is 7104121306501.

1056031214017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 500087994561 + 555943219456 = 707169^2 + 745616^2 .

It is a cyclic number.

It is not a de Polignac number, because 1056031214017 - 2²³ = 1056022825409 is a prime.

It is a super-2 number, since 2×1056031214017² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1056031214017.

It is not an unprimeable number, because it can be changed into a prime (1056031214087) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40616585142 + ... + 40616585167.

It is an arithmetic number, because the mean of its divisors is an integer number (284316096085).

Almost surely, 2^{1056031214017} is an apocalyptic number.

It is an amenable number.

1056031214017 is a deficient number, since it is larger than the sum of its proper divisors (81233170323).

1056031214017 is an equidigital number, since it uses as much as digits as its factorization.

1056031214017 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81233170322.

The product of its (nonzero) digits is 5040, while the sum is 31.

The spelling of 1056031214017 in words is "one trillion, fifty-six billion, thirty-one million, two hundred fourteen thousand, seventeen".