10646312502131 has 4 divisors (see below), whose sum is σ = 10655404145064. Its totient is φ = 10637220859200.

The previous prime is 10646312502101. The next prime is 10646312502173. The reversal of 10646312502131 is 13120521364601.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10646312502131 - 2²² = 10646308307827 is a prime.

It is a super-4 number, since 4×10646312502131⁴ (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10646312502091 and 10646312502100.

It is not an unprimeable number, because it can be changed into a prime (10646312502101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4545819710 + ... + 4545822051.

It is an arithmetic number, because the mean of its divisors is an integer number (2663851036266).

Almost surely, 2^{10646312502131} is an apocalyptic number.

10646312502131 is a deficient number, since it is larger than the sum of its proper divisors (9091642933).

10646312502131 is an equidigital number, since it uses as much as digits as its factorization.

10646312502131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9091642932.

The product of its (nonzero) digits is 25920, while the sum is 35.

Adding to 10646312502131 its reverse (13120521364601), we get a palindrome (23766833866732).

The spelling of 10646312502131 in words is "ten trillion, six hundred forty-six billion, three hundred twelve million, five hundred two thousand, one hundred thirty-one".