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10666034153 = 41592564567
BaseRepresentation
bin10011110111011111…
…01100001111101001
31000112100000200012222
421323233230033221
5133321001043103
64522214043425
7525212536325
oct117357541751
930470020188
1010666034153
114583775365
122098049575
13100c996718
147327b8985
154265c1638
hex27bbec3e9

10666034153 has 4 divisors (see below), whose sum is σ = 10668602880. Its totient is φ = 10663465428.

The previous prime is 10666034147. The next prime is 10666034173. The reversal of 10666034153 is 35143066601.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35143066601 = 53476572483.

It is a cyclic number.

It is not a de Polignac number, because 10666034153 - 28 = 10666033897 is a prime.

It is a super-3 number, since 3×106660341533 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10666034173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1278125 + ... + 1286442.

It is an arithmetic number, because the mean of its divisors is an integer number (2667150720).

Almost surely, 210666034153 is an apocalyptic number.

It is an amenable number.

10666034153 is a deficient number, since it is larger than the sum of its proper divisors (2568727).

10666034153 is an equidigital number, since it uses as much as digits as its factorization.

10666034153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2568726.

The product of its (nonzero) digits is 38880, while the sum is 35.

The spelling of 10666034153 in words is "ten billion, six hundred sixty-six million, thirty-four thousand, one hundred fifty-three".

Divisors: 1 4159 2564567 10666034153