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107126504393 = 238344954471
BaseRepresentation
bin110001111000100111…
…1001011101111001001
3101020111211102021102212
41203301033023233021
53223343341120033
6121114020434505
710511460156146
oct1436117135711
9336454367385
10107126504393
1141483134357
1218918548a35
13a1430a904c
14528370b3cd
152bbebe1748
hex18f13cbbc9

107126504393 has 4 divisors (see below), whose sum is σ = 107171461248. Its totient is φ = 107081547540.

The previous prime is 107126504389. The next prime is 107126504423. The reversal of 107126504393 is 393405621701.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 107126504393 - 22 = 107126504389 is a prime.

It is a super-2 number, since 2×1071265043932 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 107126504393.

It is not an unprimeable number, because it can be changed into a prime (107126504333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22474853 + ... + 22479618.

It is an arithmetic number, because the mean of its divisors is an integer number (26792865312).

Almost surely, 2107126504393 is an apocalyptic number.

It is an amenable number.

107126504393 is a deficient number, since it is larger than the sum of its proper divisors (44956855).

107126504393 is an equidigital number, since it uses as much as digits as its factorization.

107126504393 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44956854.

The product of its (nonzero) digits is 136080, while the sum is 41.

The spelling of 107126504393 in words is "one hundred seven billion, one hundred twenty-six million, five hundred four thousand, three hundred ninety-three".

Divisors: 1 2383 44954471 107126504393