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10752113 = 47922447
BaseRepresentation
bin101001000001…
…000001110001
3202020021010102
4221001001301
510223031423
61022242145
7160251161
oct51010161
922207112
1010752113
116084249
123726355
1322c5cc8
1415dc5a1
15e25c28
hexa41071

10752113 has 4 divisors (see below), whose sum is σ = 10775040. Its totient is φ = 10729188.

The previous prime is 10752059. The next prime is 10752121. The reversal of 10752113 is 31125701.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31125701 = 64348407.

It is a cyclic number.

It is not a de Polignac number, because 10752113 - 28 = 10751857 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (10752173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10745 + ... + 11702.

It is an arithmetic number, because the mean of its divisors is an integer number (2693760).

Almost surely, 210752113 is an apocalyptic number.

It is an amenable number.

10752113 is a deficient number, since it is larger than the sum of its proper divisors (22927).

10752113 is an equidigital number, since it uses as much as digits as its factorization.

10752113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22926.

The product of its (nonzero) digits is 210, while the sum is 20.

The square root of 10752113 is about 3279.0414757975. The cubic root of 10752113 is about 220.7147073182.

Adding to 10752113 its reverse (31125701), we get a palindrome (41877814).

The spelling of 10752113 in words is "ten million, seven hundred fifty-two thousand, one hundred thirteen".

Divisors: 1 479 22447 10752113