1092491401 has 4 divisors (see below), whose sum is σ = 1105654032. Its totient is φ = 1079328772.

The previous prime is 1092491369. The next prime is 1092491437. The reversal of 1092491401 is 1041942901.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1092491401 - 2⁵ = 1092491369 is a prime.

It is a super-3 number, since 3×1092491401³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1092491201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6581191 + ... + 6581356.

It is an arithmetic number, because the mean of its divisors is an integer number (276413508).

Almost surely, 2^1092491401 is an apocalyptic number.

It is an amenable number.

1092491401 is a deficient number, since it is larger than the sum of its proper divisors (13162631).

1092491401 is an equidigital number, since it uses as much as digits as its factorization.

1092491401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13162630.

The product of its (nonzero) digits is 2592, while the sum is 31.

The square root of 1092491401 is about 33052.8576828086. The cubic root of 1092491401 is about 1029.9259697947.

The spelling of 1092491401 in words is "one billion, ninety-two million, four hundred ninety-one thousand, four hundred one".