10943350350035 has 16 divisors (see below), whose sum is σ = 13164546850560. Its totient is φ = 8732999758560.

The previous prime is 10943350350019. The next prime is 10943350350073. The reversal of 10943350350035 is 53005305334901.

10943350350035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 10943350350035 - 2⁴ = 10943350350019 is a prime.

It is a super-2 number, since 2×10943350350035² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10943350349974 and 10943350350001.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23617940 + ... + 24076830.

It is an arithmetic number, because the mean of its divisors is an integer number (822784178160).

Almost surely, 2^{10943350350035} is an apocalyptic number.

10943350350035 is a deficient number, since it is larger than the sum of its proper divisors (2221196500525).

10943350350035 is a wasteful number, since it uses less digits than its factorization.

10943350350035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 470698.

The product of its (nonzero) digits is 364500, while the sum is 41.

Adding to 10943350350035 its reverse (53005305334901), we get a palindrome (63948655684936).

The spelling of 10943350350035 in words is "ten trillion, nine hundred forty-three billion, three hundred fifty million, three hundred fifty thousand, thirty-five".