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11000021130403 = 37623129237413
BaseRepresentation
bin1010000000010010010001…
…0110100001110010100011
31102221120222101102012202221
42200010210112201302203
52420211020402133103
635221201232251511
72213503530611104
oct240044426416243
942846871365687
1011000021130403
1135610a0181558
121297a649a0b97
1361a3b3911b56
142a05922b63ab
151412084801bd
hexa01245a1ca3

11000021130403 has 4 divisors (see below), whose sum is σ = 11000050744048. Its totient is φ = 10999991516760.

The previous prime is 11000021130389. The next prime is 11000021130421. The reversal of 11000021130403 is 30403112000011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11000021130403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11000021130443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14242476 + ... + 14994937.

It is an arithmetic number, because the mean of its divisors is an integer number (2750012686012).

Almost surely, 211000021130403 is an apocalyptic number.

11000021130403 is a deficient number, since it is larger than the sum of its proper divisors (29613645).

11000021130403 is an equidigital number, since it uses as much as digits as its factorization.

11000021130403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29613644.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 11000021130403 its reverse (30403112000011), we get a palindrome (41403133130414).

The spelling of 11000021130403 in words is "eleven trillion, twenty-one million, one hundred thirty thousand, four hundred three".

Divisors: 1 376231 29237413 11000021130403