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11000031323 = 19578949017
BaseRepresentation
bin10100011111010011…
…10010100001011011
31001101121111111012112
422033221302201123
5140012002000243
65015304502535
7536406503111
oct121751624133
931347444175
1011000031323
11473525a386
12216ba7aa4b
131063c38998
14764cbbab1
15445a98818
hex28fa7285b

11000031323 has 4 divisors (see below), whose sum is σ = 11578980360. Its totient is φ = 10421082288.

The previous prime is 11000031307. The next prime is 11000031379. The reversal of 11000031323 is 32313000011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11000031323 - 24 = 11000031307 is a prime.

It is a super-2 number, since 2×110000313232 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11000031298 and 11000031307.

It is not an unprimeable number, because it can be changed into a prime (11000031023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 289474490 + ... + 289474527.

It is an arithmetic number, because the mean of its divisors is an integer number (2894745090).

Almost surely, 211000031323 is an apocalyptic number.

11000031323 is a deficient number, since it is larger than the sum of its proper divisors (578949037).

11000031323 is an equidigital number, since it uses as much as digits as its factorization.

11000031323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 578949036.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 11000031323 its reverse (32313000011), we get a palindrome (43313031334).

The spelling of 11000031323 in words is "eleven billion, thirty-one thousand, three hundred twenty-three".

Divisors: 1 19 578949017 11000031323