11000110101113 has 4 divisors (see below), whose sum is σ = 12571554401280. Its totient is φ = 9428665800948.

The previous prime is 11000110101107. The next prime is 11000110101119. The reversal of 11000110101113 is 31110101100011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (11000110101107) and next prime (11000110101119).

It is a cyclic number.

It is not a de Polignac number, because 11000110101113 - 2⁴² = 6602063590009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11000110101094 and 11000110101103.

It is not an unprimeable number, because it can be changed into a prime (11000110101119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 785722150073 + ... + 785722150086.

It is an arithmetic number, because the mean of its divisors is an integer number (3142888600320).

Almost surely, 2^{11000110101113} is an apocalyptic number.

It is an amenable number.

11000110101113 is a deficient number, since it is larger than the sum of its proper divisors (1571444300167).

11000110101113 is an equidigital number, since it uses as much as digits as its factorization.

11000110101113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1571444300166.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 11000110101113 its reverse (31110101100011), we get a palindrome (42110211201124).

The spelling of 11000110101113 in words is "eleven trillion, one hundred ten million, one hundred one thousand, one hundred thirteen".