Base | Representation |
---|---|
bin | 1010000000010010101011… |
… | …0111011110100101100011 |
3 | 1102221121021000002021110110 |
4 | 2200010222313132211203 |
5 | 2420211231342300311 |
6 | 35221220135102403 |
7 | 2213506325631516 |
oct | 240045267364543 |
9 | 42847230067413 |
10 | 11000130431331 |
11 | 35611469459a8 |
12 | 1297a95511a03 |
13 | 61a400460c62 |
14 | 2a05a2a08d7d |
15 | 141212d708a6 |
hex | a012adde963 |
11000130431331 has 16 divisors (see below), whose sum is σ = 14926666055840. Its totient is φ = 7203820216320.
The previous prime is 11000130431317. The next prime is 11000130431363. The reversal of 11000130431331 is 13313403100011.
It is not a de Polignac number, because 11000130431331 - 210 = 11000130430307 is a prime.
It is a super-2 number, since 2×110001304313312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11000130431298 and 11000130431307.
It is not an unprimeable number, because it can be changed into a prime (11000130431531) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38942500 + ... + 39223953.
It is an arithmetic number, because the mean of its divisors is an integer number (932916628490).
Almost surely, 211000130431331 is an apocalyptic number.
11000130431331 is a deficient number, since it is larger than the sum of its proper divisors (3926535624509).
11000130431331 is an equidigital number, since it uses as much as digits as its factorization.
11000130431331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 78167286.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 11000130431331 its reverse (13313403100011), we get a palindrome (24313533531342).
The spelling of 11000130431331 in words is "eleven trillion, one hundred thirty million, four hundred thirty-one thousand, three hundred thirty-one".
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