11000131102003 has 4 divisors (see below), whose sum is σ = 11000220621400. Its totient is φ = 11000041582608.

The previous prime is 11000131101997. The next prime is 11000131102057. The reversal of 11000131102003 is 30020113100011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11000131102003 is a prime.

It is a super-2 number, since 2×11000131102003² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11000131109003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44575125 + ... + 44821222.

It is an arithmetic number, because the mean of its divisors is an integer number (2750055155350).

Almost surely, 2^{11000131102003} is an apocalyptic number.

11000131102003 is a deficient number, since it is larger than the sum of its proper divisors (89519397).

11000131102003 is an equidigital number, since it uses as much as digits as its factorization.

11000131102003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 89519396.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11000131102003 its reverse (30020113100011), we get a palindrome (41020244202014).

The spelling of 11000131102003 in words is "eleven trillion, one hundred thirty-one million, one hundred two thousand, three".