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1100013230113 = 7616325498093
BaseRepresentation
bin10000000000011101111…
…001011101100000100001
310220011022210221221000221
4100000131321131200201
5121010311341330423
62201201125043041
7142321232116210
oct20003571354041
93804283857027
101100013230113
11394570877a76
12159234256481
137c96675b145
143b35314d077
151d931c15e5d
hex1001de5d821

1100013230113 has 8 divisors (see below), whose sum is σ = 1257362011328. Its totient is φ = 942715457424.

The previous prime is 1100013230111. The next prime is 1100013230131. The reversal of 1100013230113 is 3110323100011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1100013230113 - 21 = 1100013230111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1100013230111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12705906 + ... + 12792187.

It is an arithmetic number, because the mean of its divisors is an integer number (157170251416).

Almost surely, 21100013230113 is an apocalyptic number.

It is an amenable number.

1100013230113 is a deficient number, since it is larger than the sum of its proper divisors (157348781215).

1100013230113 is an equidigital number, since it uses as much as digits as its factorization.

1100013230113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25504263.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1100013230113 its reverse (3110323100011), we get a palindrome (4210336330124).

The spelling of 1100013230113 in words is "one trillion, one hundred billion, thirteen million, two hundred thirty thousand, one hundred thirteen".

Divisors: 1 7 6163 43141 25498093 178486651 157144747159 1100013230113