110001324433 has 16 divisors (see below), whose sum is σ = 147694087296. Its totient is φ = 79121831040.

The previous prime is 110001324409. The next prime is 110001324439. The reversal of 110001324433 is 334423100011.

It is a de Polignac number, because none of the positive numbers 2^k-110001324433 is a prime.

It is not an unprimeable number, because it can be changed into a prime (110001324439) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 54944716 + ... + 54946717.

It is an arithmetic number, because the mean of its divisors is an integer number (9230880456).

Almost surely, 2^110001324433 is an apocalyptic number.

110001324433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

110001324433 is a deficient number, since it is larger than the sum of its proper divisors (37692762863).

110001324433 is a wasteful number, since it uses less digits than its factorization.

110001324433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109891464.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 110001324433 its reverse (334423100011), we get a palindrome (444424424444).

It can be divided in two parts, 110001 and 324433, that added together give a palindrome (434434).

The spelling of 110001324433 in words is "one hundred ten billion, one million, three hundred twenty-four thousand, four hundred thirty-three".