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11000153 = 54120333
BaseRepresentation
bin101001111101…
…100101011001
3202200212101002
4221331211121
510304001103
61031434345
7162333263
oct51754531
922625332
1011000153
11623363a
1238259b5
132381b88
141664b33
15e74488
hexa7d959

11000153 has 4 divisors (see below), whose sum is σ = 11021028. Its totient is φ = 10979280.

The previous prime is 11000149. The next prime is 11000159. The reversal of 11000153 is 35100011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 35100011 = 191847369.

It can be written as a sum of positive squares in 2 ways, for example, as 8133904 + 2866249 = 2852^2 + 1693^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000153 - 22 = 11000149 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11000159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9626 + ... + 10707.

It is an arithmetic number, because the mean of its divisors is an integer number (2755257).

Almost surely, 211000153 is an apocalyptic number.

It is an amenable number.

11000153 is a deficient number, since it is larger than the sum of its proper divisors (20875).

11000153 is an equidigital number, since it uses as much as digits as its factorization.

11000153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20874.

The product of its (nonzero) digits is 15, while the sum is 11.

The square root of 11000153 is about 3316.6478558931. The cubic root of 11000153 is about 222.3990401702.

Adding to 11000153 its reverse (35100011), we get a palindrome (46100164).

The spelling of 11000153 in words is "eleven million, one hundred fifty-three", and thus it is an aban number.

Divisors: 1 541 20333 11000153