11000200233131 has 4 divisors (see below), whose sum is σ = 11000235629112. Its totient is φ = 11000164837152.

The previous prime is 11000200233103. The next prime is 11000200233149. The reversal of 11000200233131 is 13133200200011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11000200233131 - 2⁴² = 6602153722027 is a prime.

It is a super-2 number, since 2×11000200233131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11000200235131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17227661 + ... + 17854766.

It is an arithmetic number, because the mean of its divisors is an integer number (2750058907278).

Almost surely, 2^{11000200233131} is an apocalyptic number.

11000200233131 is a deficient number, since it is larger than the sum of its proper divisors (35395981).

11000200233131 is an equidigital number, since it uses as much as digits as its factorization.

11000200233131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35395980.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 11000200233131 its reverse (13133200200011), we get a palindrome (24133400433142).

The spelling of 11000200233131 in words is "eleven trillion, two hundred million, two hundred thirty-three thousand, one hundred thirty-one".