11000222330113 has 4 divisors (see below), whose sum is σ = 11000348962560. Its totient is φ = 11000095697668.

The previous prime is 11000222330099. The next prime is 11000222330137. The reversal of 11000222330113 is 31103322200011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11000222330113 - 2⁵ = 11000222330081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11000222330183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63185833 + ... + 63359686.

It is an arithmetic number, because the mean of its divisors is an integer number (2750087240640).

Almost surely, 2^{11000222330113} is an apocalyptic number.

It is an amenable number.

11000222330113 is a deficient number, since it is larger than the sum of its proper divisors (126632447).

11000222330113 is an equidigital number, since it uses as much as digits as its factorization.

11000222330113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 126632446.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 11000222330113 its reverse (31103322200011), we get a palindrome (42103544530124).

The spelling of 11000222330113 in words is "eleven trillion, two hundred twenty-two million, three hundred thirty thousand, one hundred thirteen".