1100030120113 has 8 divisors (see below), whose sum is σ = 1118877724800. Its totient is φ = 1081189283088.

The previous prime is 1100030120107. The next prime is 1100030120129. The reversal of 1100030120113 is 3110210300011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1100030120113 - 2⁵ = 1100030120081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1100030120093 and 1100030120102.

It is not an unprimeable number, because it can be changed into a prime (1100030120143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1363506 + ... + 2014747.

It is an arithmetic number, because the mean of its divisors is an integer number (139859715600).

Almost surely, 2^{1100030120113} is an apocalyptic number.

It is an amenable number.

1100030120113 is a deficient number, since it is larger than the sum of its proper divisors (18847604687).

1100030120113 is an equidigital number, since it uses as much as digits as its factorization.

1100030120113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3383831.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1100030120113 its reverse (3110210300011), we get a palindrome (4210240420124).

The spelling of 1100030120113 in words is "one trillion, one hundred billion, thirty million, one hundred twenty thousand, one hundred thirteen".