Base | Representation |
---|---|
bin | 10000000000011110111… |
… | …001111011111110100011 |
3 | 10220011100222202122020121 |
4 | 100000132321323332203 |
5 | 121010330203212011 |
6 | 2201202531221111 |
7 | 142321525563220 |
oct | 20003671737643 |
9 | 3804328678217 |
10 | 1100030132131 |
11 | 39457a371787 |
12 | 159239a47797 |
13 | 7c96a0c8438 |
14 | 3b3554ac947 |
15 | 1d933453e71 |
hex | 1001ee7bfa3 |
1100030132131 has 8 divisors (see below), whose sum is σ = 1257540982880. Its totient is φ = 942610203648.
The previous prime is 1100030132063. The next prime is 1100030132237. The reversal of 1100030132131 is 1312310300011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1100030132131 - 211 = 1100030130083 is a prime.
It is a super-3 number, since 3×11000301321313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (1100030135131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22704636 + ... + 22753033.
It is an arithmetic number, because the mean of its divisors is an integer number (157192622860).
Almost surely, 21100030132131 is an apocalyptic number.
1100030132131 is a deficient number, since it is larger than the sum of its proper divisors (157510850749).
1100030132131 is an equidigital number, since it uses as much as digits as its factorization.
1100030132131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45461133.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1100030132131 its reverse (1312310300011), we get a palindrome (2412340432142).
The spelling of 1100030132131 in words is "one trillion, one hundred billion, thirty million, one hundred thirty-two thousand, one hundred thirty-one".
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