Base | Representation |
---|---|
bin | 1010000000010011010100… |
… | …1001111001001101011011 |
3 | 1102221121201000212020212122 |
4 | 2200010311021321031123 |
5 | 2420212110033444011 |
6 | 35221245222331455 |
7 | 2213513522666111 |
oct | 240046511711533 |
9 | 42847630766778 |
10 | 11000303031131 |
11 | 3561225313767 |
12 | 1297b23289b8b |
13 | 61a42a14370b |
14 | 2a05bb8d7ab1 |
15 | 1412230b63db |
hex | a013527935b |
11000303031131 has 8 divisors (see below), whose sum is σ = 11032164372480. Its totient is φ = 10968442611048.
The previous prime is 11000303031101. The next prime is 11000303031169. The reversal of 11000303031131 is 13113030300011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11000303031131 - 214 = 11000303014747 is a prime.
It is a super-3 number, since 3×110003030311313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11000303031101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29070710 + ... + 29446676.
It is an arithmetic number, because the mean of its divisors is an integer number (1379020546560).
Almost surely, 211000303031131 is an apocalyptic number.
11000303031131 is a deficient number, since it is larger than the sum of its proper divisors (31861341349).
11000303031131 is an equidigital number, since it uses as much as digits as its factorization.
11000303031131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 460633.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 11000303031131 its reverse (13113030300011), we get a palindrome (24113333331142).
The spelling of 11000303031131 in words is "eleven trillion, three hundred three million, thirty-one thousand, one hundred thirty-one".
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