11000312131 has 4 divisors (see below), whose sum is σ = 11031832000. Its totient is φ = 10968792264.

The previous prime is 11000312129. The next prime is 11000312201. The reversal of 11000312131 is 13121300011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13121300011 = 7177 ⋅1828243.

It is a cyclic number.

It is not a de Polignac number, because 11000312131 - 2¹ = 11000312129 is a prime.

It is a super-3 number, since 3×11000312131³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11000312431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15759411 + ... + 15760108.

It is an arithmetic number, because the mean of its divisors is an integer number (2757958000).

Almost surely, 2^11000312131 is an apocalyptic number.

11000312131 is a deficient number, since it is larger than the sum of its proper divisors (31519869).

11000312131 is an equidigital number, since it uses as much as digits as its factorization.

11000312131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31519868.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11000312131 its reverse (13121300011), we get a palindrome (24121612142).

The spelling of 11000312131 in words is "eleven billion, three hundred twelve thousand, one hundred thirty-one".