1100031230113 has 4 divisors (see below), whose sum is σ = 1100924839168. Its totient is φ = 1099137621060.

The previous prime is 1100031230063. The next prime is 1100031230131. The reversal of 1100031230113 is 3110321300011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1100031230113 - 2¹³ = 1100031221921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1100031233113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 446802681 + ... + 446805142.

It is an arithmetic number, because the mean of its divisors is an integer number (275231209792).

Almost surely, 2^{1100031230113} is an apocalyptic number.

It is an amenable number.

1100031230113 is a deficient number, since it is larger than the sum of its proper divisors (893609055).

1100031230113 is an equidigital number, since it uses as much as digits as its factorization.

1100031230113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 893609054.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1100031230113 its reverse (3110321300011), we get a palindrome (4210352530124).

The spelling of 1100031230113 in words is "one trillion, one hundred billion, thirty-one million, two hundred thirty thousand, one hundred thirteen".