11000323113 has 8 divisors (see below), whose sum is σ = 15795335808. Its totient is φ = 6769429584.

The previous prime is 11000323111. The next prime is 11000323129. The reversal of 11000323113 is 31132300011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11000323113 - 2¹ = 11000323111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11000323092 and 11000323101.

It is not an unprimeable number, because it can be changed into a prime (11000323111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 141029745 + ... + 141029822.

It is an arithmetic number, because the mean of its divisors is an integer number (1974416976).

Almost surely, 2^11000323113 is an apocalyptic number.

11000323113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11000323113 is a deficient number, since it is larger than the sum of its proper divisors (4795012695).

11000323113 is a wasteful number, since it uses less digits than its factorization.

11000323113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 282059583.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11000323113 its reverse (31132300011), we get a palindrome (42132623124).

The spelling of 11000323113 in words is "eleven billion, three hundred twenty-three thousand, one hundred thirteen".