Base | Representation |
---|---|
bin | 1010000000010011011011… |
… | …1000111100101101011011 |
3 | 1102221121210001122022110201 |
4 | 2200010312320330231123 |
5 | 2420212140012042301 |
6 | 35221252142323031 |
7 | 2213514325306510 |
oct | 240046670745533 |
9 | 42847701568421 |
10 | 11000332143451 |
11 | 356123a798232 |
12 | 1297b30b89477 |
13 | 61a433197641 |
14 | 2a05c1715307 |
15 | 141225917201 |
hex | a0136e3cb5b |
11000332143451 has 16 divisors (see below), whose sum is σ = 12646573967104. Its totient is φ = 9372946459104.
The previous prime is 11000332143413. The next prime is 11000332143469. The reversal of 11000332143451 is 15434123300011.
11000332143451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 11000332143451 - 29 = 11000332142939 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11000332141451) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6060105 + ... + 7663258.
It is an arithmetic number, because the mean of its divisors is an integer number (790410872944).
Almost surely, 211000332143451 is an apocalyptic number.
11000332143451 is a deficient number, since it is larger than the sum of its proper divisors (1646241823653).
11000332143451 is a wasteful number, since it uses less digits than its factorization.
11000332143451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13724050.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 11000332143451 its reverse (15434123300011), we get a palindrome (26434455443462).
The spelling of 11000332143451 in words is "eleven trillion, three hundred thirty-two million, one hundred forty-three thousand, four hundred fifty-one".
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