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11000340003041 = 178921112912779
BaseRepresentation
bin1010000000010011011101…
…0110111011100011100001
31102221121210121102121210122
42200010313112323203201
52420212144020044131
635221253023010025
72213514452152664
oct240046726734341
942847717377718
1011000340003041
113561244176264
121297b33739915
1361a4349b9b9c
142a05c279d6db
1514122646ad7b
hexa01375bb8e1

11000340003041 has 8 divisors (see below), whose sum is σ = 11011706534400. Its totient is φ = 10988979305040.

The previous prime is 11000340003031. The next prime is 11000340003077. The reversal of 11000340003041 is 14030004300011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11000340003041 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11000340003031) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2320190 + ... + 5232968.

It is an arithmetic number, because the mean of its divisors is an integer number (1376463316800).

Almost surely, 211000340003041 is an apocalyptic number.

It is an amenable number.

11000340003041 is a deficient number, since it is larger than the sum of its proper divisors (11366531359).

11000340003041 is a wasteful number, since it uses less digits than its factorization.

11000340003041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2916679.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 11000340003041 its reverse (14030004300011), we get a palindrome (25030344303052).

The spelling of 11000340003041 in words is "eleven trillion, three hundred forty million, three thousand, forty-one".

Divisors: 1 1789 2111 2912779 3776579 5210961631 6148876469 11000340003041