110005532481913 has 4 divisors (see below), whose sum is σ = 110411456956288. Its totient is φ = 109599608007540.

The previous prime is 110005532481883. The next prime is 110005532481991. The reversal of 110005532481913 is 319184235500011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110005532481913 - 2¹³ = 110005532473721 is a prime.

It is a super-2 number, since 2×110005532481913² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 110005532481913.

It is not an unprimeable number, because it can be changed into a prime (110005532482913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202962236781 + ... + 202962237322.

It is an arithmetic number, because the mean of its divisors is an integer number (27602864239072).

Almost surely, 2^{110005532481913} is an apocalyptic number.

It is an amenable number.

110005532481913 is a deficient number, since it is larger than the sum of its proper divisors (405924474375).

110005532481913 is an equidigital number, since it uses as much as digits as its factorization.

110005532481913 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 405924474374.

The product of its (nonzero) digits is 129600, while the sum is 43.

Adding to 110005532481913 its reverse (319184235500011), we get a palindrome (429189767981924).

The spelling of 110005532481913 in words is "one hundred ten trillion, five billion, five hundred thirty-two million, four hundred eighty-one thousand, nine hundred thirteen".