1100101133011 has 4 divisors (see below), whose sum is σ = 1102305745000. Its totient is φ = 1097896521024.

The previous prime is 1100101133009. The next prime is 1100101133023. The reversal of 1100101133011 is 1103311010011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1100101133011 - 2¹ = 1100101133009 is a prime.

It is a super-2 number, since 2×1100101133011² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1100101132982 and 1100101133000.

It is not an unprimeable number, because it can be changed into a prime (1100101133071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1102305246 + ... + 1102306243.

It is an arithmetic number, because the mean of its divisors is an integer number (275576436250).

Almost surely, 2^{1100101133011} is an apocalyptic number.

1100101133011 is a deficient number, since it is larger than the sum of its proper divisors (2204611989).

1100101133011 is an equidigital number, since it uses as much as digits as its factorization.

1100101133011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2204611988.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 1100101133011 its reverse (1103311010011), we get a palindrome (2203412143022).

The spelling of 1100101133011 in words is "one trillion, one hundred billion, one hundred one million, one hundred thirty-three thousand, eleven".