1100101314155 has 4 divisors (see below), whose sum is σ = 1320121576992. Its totient is φ = 880081051320.

The previous prime is 1100101314121. The next prime is 1100101314181. The reversal of 1100101314155 is 5514131010011.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2^k-1100101314155 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1100101314155.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110010131411 + ... + 110010131420.

It is an arithmetic number, because the mean of its divisors is an integer number (330030394248).

Almost surely, 2^{1100101314155} is an apocalyptic number.

1100101314155 is a deficient number, since it is larger than the sum of its proper divisors (220020262837).

1100101314155 is an equidigital number, since it uses as much as digits as its factorization.

1100101314155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 220020262836.

The product of its (nonzero) digits is 300, while the sum is 23.

Adding to 1100101314155 its reverse (5514131010011), we get a palindrome (6614232324166).

The spelling of 1100101314155 in words is "one trillion, one hundred billion, one hundred one million, three hundred fourteen thousand, one hundred fifty-five".