Base | Representation |
---|---|
bin | 11001000000110110111111… |
… | …100111010101001010011011 |
3 | 112102111212120211102202211112 |
4 | 121000312333213111022123 |
5 | 103404401403300023003 |
6 | 1025545554352450535 |
7 | 32112655416160121 |
oct | 3100667747251233 |
9 | 472455524382745 |
10 | 110010212111003 |
11 | 3206408385a356 |
12 | 10408871549a4b |
13 | 494cbc2bc65a9 |
14 | 1d24746319911 |
15 | cab94101d3d8 |
hex | 640dbf9d529b |
110010212111003 has 16 divisors (see below), whose sum is σ = 116044511452320. Its totient is φ = 104000571737856.
The previous prime is 110010212110859. The next prime is 110010212111057. The reversal of 110010212111003 is 300111212010011.
It is a cyclic number.
It is not a de Polignac number, because 110010212111003 - 210 = 110010212109979 is a prime.
It is a super-2 number, since 2×1100102121110032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (110010212011003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14017301 + ... + 20408457.
It is an arithmetic number, because the mean of its divisors is an integer number (7252781965770).
Almost surely, 2110010212111003 is an apocalyptic number.
110010212111003 is a deficient number, since it is larger than the sum of its proper divisors (6034299341317).
110010212111003 is a wasteful number, since it uses less digits than its factorization.
110010212111003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6393086.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 110010212111003 its reverse (300111212010011), we get a palindrome (410121424121014).
The spelling of 110010212111003 in words is "one hundred ten trillion, ten billion, two hundred twelve million, one hundred eleven thousand, three".
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