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11001022002121 = 28873810537583
BaseRepresentation
bin1010000000010110000000…
…0000100011001111001001
31102221200120010201202122211
42200011200000203033021
52420220043113031441
635221444424345121
72213540403102334
oct240054000431711
942850503652584
1011001022002121
113561564140268
1212980a40151a1
1361a513095a38
142a06491ad61b
15141266284a81
hexa01600233c9

11001022002121 has 4 divisors (see below), whose sum is σ = 11004832542592. Its totient is φ = 10997211461652.

The previous prime is 11001022002079. The next prime is 11001022002161. The reversal of 11001022002121 is 12120022010011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11001022002121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11001022002161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1905265905 + ... + 1905271678.

It is an arithmetic number, because the mean of its divisors is an integer number (2751208135648).

Almost surely, 211001022002121 is an apocalyptic number.

It is an amenable number.

11001022002121 is a deficient number, since it is larger than the sum of its proper divisors (3810540471).

11001022002121 is an equidigital number, since it uses as much as digits as its factorization.

11001022002121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3810540470.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 11001022002121 its reverse (12120022010011), we get a palindrome (23121044012132).

The spelling of 11001022002121 in words is "eleven trillion, one billion, twenty-two million, two thousand, one hundred twenty-one".

Divisors: 1 2887 3810537583 11001022002121