1100112130003 has 4 divisors (see below), whose sum is σ = 1100124723088. Its totient is φ = 1100099536920.

The previous prime is 1100112129971. The next prime is 1100112130009. The reversal of 1100112130003 is 3000312110011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1100112130003 - 2⁵ = 1100112129971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1100112130009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6164583 + ... + 6340528.

It is an arithmetic number, because the mean of its divisors is an integer number (275031180772).

Almost surely, 2^{1100112130003} is an apocalyptic number.

1100112130003 is a deficient number, since it is larger than the sum of its proper divisors (12593085).

1100112130003 is an equidigital number, since it uses as much as digits as its factorization.

1100112130003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12593084.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1100112130003 its reverse (3000312110011), we get a palindrome (4100424240014).

The spelling of 1100112130003 in words is "one trillion, one hundred billion, one hundred twelve million, one hundred thirty thousand, three".