Base | Representation |
---|---|
bin | 1010000000010110101011… |
… | …0000000001111111001011 |
3 | 1102221201000200211211111020 |
4 | 2200011222300001333023 |
5 | 2420220430232033003 |
6 | 35221514343203523 |
7 | 2213545021661661 |
oct | 240055260017713 |
9 | 42851020754436 |
10 | 11001202221003 |
11 | 3561646942395 |
12 | 12981344465a3 |
13 | 61a541515427 |
14 | 2a06650c2c31 |
15 | 141276ed2d53 |
hex | a016ac01fcb |
11001202221003 has 8 divisors (see below), whose sum is σ = 14691966350400. Its totient is φ = 7322286452808.
The previous prime is 11001202220993. The next prime is 11001202221007. The reversal of 11001202221003 is 30012220210011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11001202221003 - 237 = 10863763267531 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11001202221007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2962088133 + ... + 2962091846.
It is an arithmetic number, because the mean of its divisors is an integer number (1836495793800).
Almost surely, 211001202221003 is an apocalyptic number.
11001202221003 is a deficient number, since it is larger than the sum of its proper divisors (3690764129397).
11001202221003 is an equidigital number, since it uses as much as digits as its factorization.
11001202221003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5924180601.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 11001202221003 its reverse (30012220210011), we get a palindrome (41013422431014).
The spelling of 11001202221003 in words is "eleven trillion, one billion, two hundred two million, two hundred twenty-one thousand, three".
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