11001211012121 has 4 divisors (see below), whose sum is σ = 12001321104144. Its totient is φ = 10001100920100.

The previous prime is 11001211012097. The next prime is 11001211012133. The reversal of 11001211012121 is 12121011210011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11001211012121 - 2¹⁴ = 11001210995737 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11001211012096 and 11001211012105.

It is not an unprimeable number, because it can be changed into a prime (11001211012621) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500055045995 + ... + 500055046016.

It is an arithmetic number, because the mean of its divisors is an integer number (3000330276036).

Almost surely, 2^{11001211012121} is an apocalyptic number.

11001211012121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

11001211012121 is a deficient number, since it is larger than the sum of its proper divisors (1000110092023).

11001211012121 is a wasteful number, since it uses less digits than its factorization.

11001211012121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1000110092022.

The product of its (nonzero) digits is 8, while the sum is 14.

Adding to 11001211012121 its reverse (12121011210011), we get a palindrome (23122222222132).

The spelling of 11001211012121 in words is "eleven trillion, one billion, two hundred eleven million, twelve thousand, one hundred twenty-one".