Base | Representation |
---|---|
bin | 10100011111011100… |
… | …10011000001001011 |
3 | 1001101200201112011110 |
4 | 22033232103001023 |
5 | 140012302304003 |
6 | 5015350101403 |
7 | 536422524204 |
oct | 121756230113 |
9 | 31350645143 |
10 | 11001213003 |
11 | 4735997180 |
12 | 217034a863 |
13 | 10642607c1 |
14 | 7651085ab |
15 | 445c2da03 |
hex | 28fb9304b |
11001213003 has 16 divisors (see below), whose sum is σ = 16240599936. Its totient is φ = 6567887040.
The previous prime is 11001212987. The next prime is 11001213011. The reversal of 11001213003 is 30031210011.
11001213003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11001213003 - 24 = 11001212987 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11001213003.
It is not an unprimeable number, because it can be changed into a prime (11001213023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2485626 + ... + 2490047.
It is an arithmetic number, because the mean of its divisors is an integer number (1015037496).
Almost surely, 211001213003 is an apocalyptic number.
11001213003 is a deficient number, since it is larger than the sum of its proper divisors (5239386933).
11001213003 is a wasteful number, since it uses less digits than its factorization.
11001213003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4975754.
The product of its (nonzero) digits is 18, while the sum is 12.
Adding to 11001213003 its reverse (30031210011), we get a palindrome (41032423014).
The spelling of 11001213003 in words is "eleven billion, one million, two hundred thirteen thousand, three".
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