110012232131113 has 4 divisors (see below), whose sum is σ = 118474711525828. Its totient is φ = 101549752736400.

The previous prime is 110012232131093. The next prime is 110012232131141. The reversal of 110012232131113 is 311131232210011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 49820827041769 + 60191405089344 = 7058387^2 + 7758312^2 .

It is a cyclic number.

It is not a de Polignac number, because 110012232131113 - 2¹³ = 110012232122921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110012232131183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4231239697338 + ... + 4231239697363.

It is an arithmetic number, because the mean of its divisors is an integer number (29618677881457).

Almost surely, 2^{110012232131113} is an apocalyptic number.

110012232131113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

110012232131113 is a deficient number, since it is larger than the sum of its proper divisors (8462479394715).

110012232131113 is an equidigital number, since it uses as much as digits as its factorization.

110012232131113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8462479394714.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 110012232131113 its reverse (311131232210011), we get a palindrome (421143464341124).

The spelling of 110012232131113 in words is "one hundred ten trillion, twelve billion, two hundred thirty-two million, one hundred thirty-one thousand, one hundred thirteen".