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1100123100313 = 5609919610387
BaseRepresentation
bin10000000000100100011…
…100100101010010011001
310220011121110200220121121
4100000210130211102121
5121011023003202223
62201220052005241
7142324035030406
oct20004434452231
93804543626547
101100123100313
113946178a0096
12159265000821
137c9834493b3
143b36398d2ad
151d93b6ba15d
hex10024725499

1100123100313 has 4 divisors (see below), whose sum is σ = 1100142766800. Its totient is φ = 1100103433828.

The previous prime is 1100123100283. The next prime is 1100123100347. The reversal of 1100123100313 is 3130013210011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1100123100313 - 25 = 1100123100281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1100123100383) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9749095 + ... + 9861292.

It is an arithmetic number, because the mean of its divisors is an integer number (275035691700).

Almost surely, 21100123100313 is an apocalyptic number.

It is an amenable number.

1100123100313 is a deficient number, since it is larger than the sum of its proper divisors (19666487).

1100123100313 is an equidigital number, since it uses as much as digits as its factorization.

1100123100313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19666486.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1100123100313 its reverse (3130013210011), we get a palindrome (4230136310324).

The spelling of 1100123100313 in words is "one trillion, one hundred billion, one hundred twenty-three million, one hundred thousand, three hundred thirteen".

Divisors: 1 56099 19610387 1100123100313