11002312013131 has 8 divisors (see below), whose sum is σ = 11279473228800. Its totient is φ = 10725570423360.

The previous prime is 11002312013129. The next prime is 11002312013141. The reversal of 11002312013131 is 13131021320011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11002312013131 - 2¹ = 11002312013129 is a prime.

It is a super-2 number, since 2×11002312013131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11002312013099 and 11002312013108.

It is not an unprimeable number, because it can be changed into a prime (11002312013101) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 104853376 + ... + 104958253.

It is an arithmetic number, because the mean of its divisors is an integer number (1409934153600).

Almost surely, 2^{11002312013131} is an apocalyptic number.

11002312013131 is a deficient number, since it is larger than the sum of its proper divisors (277161215669).

11002312013131 is a wasteful number, since it uses less digits than its factorization.

11002312013131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 209812949.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 11002312013131 its reverse (13131021320011), we get a palindrome (24133333333142).

The spelling of 11002312013131 in words is "eleven trillion, two billion, three hundred twelve million, thirteen thousand, one hundred thirty-one".