11002323320433 has 6 divisors (see below), whose sum is σ = 15892244796194. Its totient is φ = 7334882213616.

The previous prime is 11002323320411. The next prime is 11002323320473. The reversal of 11002323320433 is 33402332320011.

11002323320433 is a `hidden beast` number, since 1 + 10 + 0 + 2 + 323 + 320 + 4 + 3 + 3 = 666.

It can be written as a sum of positive squares in only one way, i.e., 8993323238769 + 2009000081664 = 2998887^2 + 1417392^2 .

It is not a de Polignac number, because 11002323320433 - 2²⁵ = 11002289766001 is a prime.

It is a super-2 number, since 2×11002323320433² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11002323320397 and 11002323320406.

It is not an unprimeable number, because it can be changed into a prime (11002323320473) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 611240184460 + ... + 611240184477.

Almost surely, 2^{11002323320433} is an apocalyptic number.

It is an amenable number.

11002323320433 is a deficient number, since it is larger than the sum of its proper divisors (4889921475761).

11002323320433 is a wasteful number, since it uses less digits than its factorization.

11002323320433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1222480368943 (or 1222480368940 counting only the distinct ones).

The product of its (nonzero) digits is 7776, while the sum is 27.

Adding to 11002323320433 its reverse (33402332320011), we get a palindrome (44404655640444).

The spelling of 11002323320433 in words is "eleven trillion, two billion, three hundred twenty-three million, three hundred twenty thousand, four hundred thirty-three".