110031222130321 has 4 divisors (see below), whose sum is σ = 113005038944692. Its totient is φ = 107057405315952.

The previous prime is 110031222130243. The next prime is 110031222130327. The reversal of 110031222130321 is 123031222130011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 94619120199696 + 15412101930625 = 9727236^2 + 3925825^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110031222130321 is a prime.

It is a super-3 number, since 3×110031222130321³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110031222130292 and 110031222130301.

It is not an unprimeable number, because it can be changed into a prime (110031222130327) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1486908407130 + ... + 1486908407203.

It is an arithmetic number, because the mean of its divisors is an integer number (28251259736173).

Almost surely, 2^{110031222130321} is an apocalyptic number.

It is an amenable number.

110031222130321 is a deficient number, since it is larger than the sum of its proper divisors (2973816814371).

110031222130321 is an equidigital number, since it uses as much as digits as its factorization.

110031222130321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2973816814370.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 110031222130321 its reverse (123031222130011), we get a palindrome (233062444260332).

The spelling of 110031222130321 in words is "one hundred ten trillion, thirty-one billion, two hundred twenty-two million, one hundred thirty thousand, three hundred twenty-one".