1100320001331 has 4 divisors (see below), whose sum is σ = 1467093335112. Its totient is φ = 733546667552.

The previous prime is 1100320001327. The next prime is 1100320001401. The reversal of 1100320001331 is 1331000230011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1100320001331 - 2² = 1100320001327 is a prime.

It is a super-2 number, since 2×1100320001331² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1100320001331.

It is not an unprimeable number, because it can be changed into a prime (1100325001331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183386666886 + ... + 183386666891.

It is an arithmetic number, because the mean of its divisors is an integer number (366773333778).

Almost surely, 2^{1100320001331} is an apocalyptic number.

1100320001331 is a deficient number, since it is larger than the sum of its proper divisors (366773333781).

1100320001331 is an equidigital number, since it uses as much as digits as its factorization.

1100320001331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 366773333780.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1100320001331 its reverse (1331000230011), we get a palindrome (2431320231342).

The spelling of 1100320001331 in words is "one trillion, one hundred billion, three hundred twenty million, one thousand, three hundred thirty-one".