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110032010113 = 1931249185323
BaseRepresentation
bin110011001111001101…
…0110011101110000001
3101112000022122020222211
41212132122303232001
53300321143310423
6122314211502121
710643460440254
oct1463632635601
9345008566884
10110032010113
1142734223853
12193a95b7941
13a4b7026abc
14547b55709b
152cded1c10d
hex199e6b3b81

110032010113 has 8 divisors (see below), whose sum is σ = 115827500000. Its totient is φ = 104236953408.

The previous prime is 110032010071. The next prime is 110032010119. The reversal of 110032010113 is 311010230011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110032010113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110032010093 and 110032010102.

It is not an unprimeable number, because it can be changed into a prime (110032010119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 501070 + ... + 686392.

It is an arithmetic number, because the mean of its divisors is an integer number (14478437500).

Almost surely, 2110032010113 is an apocalyptic number.

It is an amenable number.

110032010113 is a deficient number, since it is larger than the sum of its proper divisors (5795489887).

110032010113 is a wasteful number, since it uses less digits than its factorization.

110032010113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 216591.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 110032010113 its reverse (311010230011), we get a palindrome (421042240124).

The spelling of 110032010113 in words is "one hundred ten billion, thirty-two million, ten thousand, one hundred thirteen".

Divisors: 1 19 31249 185323 593731 3521137 5791158427 110032010113