1100320311113 has 4 divisors (see below), whose sum is σ = 1100371703760. Its totient is φ = 1100268918468.

The previous prime is 1100320311109. The next prime is 1100320311127. The reversal of 1100320311113 is 3111130230011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1100320311113 - 2² = 1100320311109 is a prime.

It is a super-2 number, since 2×1100320311113² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1100320311091 and 1100320311100.

It is not an unprimeable number, because it can be changed into a prime (1100320311133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25664195 + ... + 25707032.

It is an arithmetic number, because the mean of its divisors is an integer number (275092925940).

Almost surely, 2^{1100320311113} is an apocalyptic number.

It is an amenable number.

1100320311113 is a deficient number, since it is larger than the sum of its proper divisors (51392647).

1100320311113 is an equidigital number, since it uses as much as digits as its factorization.

1100320311113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51392646.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1100320311113 its reverse (3111130230011), we get a palindrome (4211450541124).

The spelling of 1100320311113 in words is "one trillion, one hundred billion, three hundred twenty million, three hundred eleven thousand, one hundred thirteen".