11003213242433 has 4 divisors (see below), whose sum is σ = 11003222630400. Its totient is φ = 11003203854468.

The previous prime is 11003213242393. The next prime is 11003213242459. The reversal of 11003213242433 is 33424231230011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11003213242433 - 2¹⁸ = 11003212980289 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11003213242396 and 11003213242405.

It is not an unprimeable number, because it can be changed into a prime (11003213242633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2634785 + ... + 5380382.

It is an arithmetic number, because the mean of its divisors is an integer number (2750805657600).

Almost surely, 2^{11003213242433} is an apocalyptic number.

It is an amenable number.

11003213242433 is a deficient number, since it is larger than the sum of its proper divisors (9387967).

11003213242433 is an equidigital number, since it uses as much as digits as its factorization.

11003213242433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9387966.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 11003213242433 its reverse (33424231230011), we get a palindrome (44427444472444).

The spelling of 11003213242433 in words is "eleven trillion, three billion, two hundred thirteen million, two hundred forty-two thousand, four hundred thirty-three".