Base | Representation |
---|---|
bin | 10000000000110000010… |
… | …111001000111100110001 |
3 | 10220012010101211212120220 |
4 | 100000300113020330301 |
5 | 121011430142000423 |
6 | 2201251552323253 |
7 | 142332013116561 |
oct | 20006027107461 |
9 | 3805111755526 |
10 | 1100323000113 |
11 | 39470a714837 |
12 | 1592bbb43529 |
13 | 7c9b5999bbc |
14 | 3b382346da1 |
15 | 1d94e0049e3 |
hex | 100305c8f31 |
1100323000113 has 16 divisors (see below), whose sum is σ = 1474767122496. Its totient is φ = 729714124800.
The previous prime is 1100323000061. The next prime is 1100323000121. The reversal of 1100323000113 is 3110003230011.
It is not a de Polignac number, because 1100323000113 - 213 = 1100322991921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1100323000092 and 1100323000101.
It is not an unprimeable number, because it can be changed into a prime (1100323000163) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22093506 + ... + 22143252.
It is an arithmetic number, because the mean of its divisors is an integer number (92172945156).
Almost surely, 21100323000113 is an apocalyptic number.
It is an amenable number.
1100323000113 is a deficient number, since it is larger than the sum of its proper divisors (374444122383).
1100323000113 is a wasteful number, since it uses less digits than its factorization.
1100323000113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 88144.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 1100323000113 its reverse (3110003230011), we get a palindrome (4210326230124).
The spelling of 1100323000113 in words is "one trillion, one hundred billion, three hundred twenty-three million, one hundred thirteen", and thus it is an aban number.
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