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1100323000113 = 31933820149747
BaseRepresentation
bin10000000000110000010…
…111001000111100110001
310220012010101211212120220
4100000300113020330301
5121011430142000423
62201251552323253
7142332013116561
oct20006027107461
93805111755526
101100323000113
1139470a714837
121592bbb43529
137c9b5999bbc
143b382346da1
151d94e0049e3
hex100305c8f31

1100323000113 has 16 divisors (see below), whose sum is σ = 1474767122496. Its totient is φ = 729714124800.

The previous prime is 1100323000061. The next prime is 1100323000121. The reversal of 1100323000113 is 3110003230011.

It is not a de Polignac number, because 1100323000113 - 213 = 1100322991921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100323000092 and 1100323000101.

It is not an unprimeable number, because it can be changed into a prime (1100323000163) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22093506 + ... + 22143252.

It is an arithmetic number, because the mean of its divisors is an integer number (92172945156).

Almost surely, 21100323000113 is an apocalyptic number.

It is an amenable number.

1100323000113 is a deficient number, since it is larger than the sum of its proper divisors (374444122383).

1100323000113 is a wasteful number, since it uses less digits than its factorization.

1100323000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 88144.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1100323000113 its reverse (3110003230011), we get a palindrome (4210326230124).

The spelling of 1100323000113 in words is "one trillion, one hundred billion, three hundred twenty-three million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 3 193 579 38201 49747 114603 149241 7372793 9601171 22118379 28803513 1900385147 5701155441 366774333371 1100323000113