11003331013001 has 4 divisors (see below), whose sum is σ = 11259222431952. Its totient is φ = 10747439594052.

The previous prime is 11003331012977. The next prime is 11003331013009. The reversal of 11003331013001 is 10031013330011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11003331013001 - 2⁶ = 11003331012937 is a prime.

It is a super-2 number, since 2×11003331013001² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11003331013009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127945709411 + ... + 127945709496.

It is an arithmetic number, because the mean of its divisors is an integer number (2814805607988).

Almost surely, 2^{11003331013001} is an apocalyptic number.

It is an amenable number.

11003331013001 is a deficient number, since it is larger than the sum of its proper divisors (255891418951).

11003331013001 is an equidigital number, since it uses as much as digits as its factorization.

11003331013001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 255891418950.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 11003331013001 its reverse (10031013330011), we get a palindrome (21034344343012).

The spelling of 11003331013001 in words is "eleven trillion, three billion, three hundred thirty-one million, thirteen thousand, one".