110034140044331 has 4 divisors (see below), whose sum is σ = 115825410573000. Its totient is φ = 104242869515664.

The previous prime is 110034140044327. The next prime is 110034140044333. The reversal of 110034140044331 is 133440041430011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 110034140044331 - 2² = 110034140044327 is a prime.

It is a super-2 number, since 2×110034140044331² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110034140044294 and 110034140044303.

It is not an unprimeable number, because it can be changed into a prime (110034140044333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2895635264306 + ... + 2895635264343.

It is an arithmetic number, because the mean of its divisors is an integer number (28956352643250).

Almost surely, 2^{110034140044331} is an apocalyptic number.

110034140044331 is a deficient number, since it is larger than the sum of its proper divisors (5791270528669).

110034140044331 is an equidigital number, since it uses as much as digits as its factorization.

110034140044331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5791270528668.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 110034140044331 its reverse (133440041430011), we get a palindrome (243474181474342).

The spelling of 110034140044331 in words is "one hundred ten trillion, thirty-four billion, one hundred forty million, forty-four thousand, three hundred thirty-one".